## Chemistry (7th Edition)

$mass(g) = 0.0104$
1. Calculate [OH-]: pH + pOH = 14 10 + pOH = 14 pOH = 4 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 4}$ $[OH^-] = 1 \times 10^{- 4}M$ $- SrO(aq) + H_2O(l) -- \gt Sr^{2+}(aq) + 2OH^-(aq)$ 2. Since $SrO$ is a strong base that produces 2 OH for each molecule: $[OH^-] = 2 * [SrO]$ $1\times 10^{- 4} = 2 * [SrO]$ $\frac{ 1\times 10^{- 4}}{ 2} = [SrO]$ $5\times 10^{- 5}M = [SrO]$ 3. Calculate the number of moles: $n(moles) = concentration(M) * volume(L)$ $n(moles) = 5\times 10^{- 5} * 2$ $n(moles) = 1\times 10^{- 4}$ 4. Find the mass value in grams: (87.62* 1 + 16* 1) = 103.62g/mol $mass(g) = mm(g/mol) * n(moles)$ $mass(g) = 103.62 * 1\times 10^{- 4}$ $mass(g) = 0.01036$