Answer
$[H_3O^+] = [OH^-] = 4.123\times 10^{- 10}M$
The solution is neutral
Work Step by Step
- Pure water solution : $[H_3O^+] = [OH^-]$
- Create an unknown called 'x', that has the value of $[H_3O^+] and [OH^-]$
- Write the $K_w$ expression, and calculate the x value:
$[H_3O^+] * [OH^-] = K_w = 1.7\times 10^{- 19}$
$x * x = 1.7\times 10^{- 19}$
$x^2 = 1.7\times 10^{- 19}$
$x = \sqrt { 1.7\times 10^{- 19}}$
$x = 4.123\times 10^{- 10}$
Therefore: $[H_3O^+] and [OH^-] = 4.123\times 10^{- 10}M$
Since $[H_3O^+] = [OH^-]$, the solution is neutral.
