## Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company

# Chapter 4 - Questions and Problems - Page 178: 4.62

#### Answer

There are 10.8 g of potassium hydroxide in this solution.

#### Work Step by Step

$35.0 mL = 35.0 \times 10^{-3} L = 0.0350 L$ 1. Find the number of moles: $Concentration(M) = \frac{n(mol)}{V(L)}$ $5.5 = \frac{n(mol)}{0.035}$ $5.5 * 0.035 = n(mol)$ $0.193 moles = n(mol)$ 2. Determine the molar mass of this compound (KOH): 39.1* 1 + 16* 1 + 1.008* 1 = 56.108g/mol 3. Calculate the mass $mm(g/mol) = \frac{mass(g)}{n(mol)}$ $mm(g/mol) * n(mol) = mass(g)$ $56.108 * 0.193 = mass(g)$ $10.8 = mass(g)$

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