## Chemistry (4th Edition)

$5.00 \times 10^{2} mL$ = $500$ $mL$ = 0.500L 1. Find the number of moles: $Concentration(M) = \frac{n(mol)}{V(L)}$ $2.80 = \frac{n(mol)}{0.500}$ $2.80 * 0.500 = n(mol)$ $1.40\ moles = n(mol)$ 2. Determine the molar mass of this compound (KI): 39.1* 1 + 126.9* 1 = 166 g/mol 3. Calculate the mass $mm(g/mol) = \frac{mass(g)}{n(mol)}$ $mm(g/mol) * n(mol) = mass(g)$ $166 * 1.40 = mass(g)$ $232 = mass(g)$