Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 4 - Questions and Problems - Page 178: 4.61

Answer

The amount of $MgCl_2$ in moles is equal to $6.00 \times 10^{-3}$.

Work Step by Step

60.0 mL = $60.0 \times 10^{-3}$ L = 0.0600 L 1. Find the number of moles: $Concentration(M) = \frac{n(mol)}{V(L)}$ $0.100 = \frac{n(mol)}{0.0600}$ $0.100* 0.0600 = n(mol)$ $6.00 \times 10^{-3} moles = n(mol)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.