## Chemistry (4th Edition)

The amount of $MgCl_2$ in moles is equal to $6.00 \times 10^{-3}$.
60.0 mL = $60.0 \times 10^{-3}$ L = 0.0600 L 1. Find the number of moles: $Concentration(M) = \frac{n(mol)}{V(L)}$ $0.100 = \frac{n(mol)}{0.0600}$ $0.100* 0.0600 = n(mol)$ $6.00 \times 10^{-3} moles = n(mol)$