Answer
$T_2=1.3\times 10^2K$
Work Step by Step
The required final temperature can be determined as
$T_1=88+273.15=361.15K$
Now, according to Charles's law
$\frac{V_1}{T_1}=\frac{V_2}{T_2}$
This can be rearranged as
$T_2=\frac{V_2T_1}{V_1}$
We plug in the known values to obtain:
$T_2=\frac{3.4\times 361.15}{9.6}$
This simplifies to:
$T_2=1.3\times 10^2K$
