Answer
$V_2=0.69L$
$P_2=61atm$
Work Step by Step
We can determine the required pressure and volume , according to Boyle's law as follows:
$P_1V_1=P_2V_2$
This can be rearranged as
$V_2=\frac{P_1V_1}{P_2}$
We plug in the known values to obtain:
$V_2=\frac{1.2\times 3.8}{6.6}$
This simplifies to:
$V_2=0.69L$
Now, $P_2$ can be calculated as
$P_2=\frac{P_1V_1}{V_2}$
We plug in the known values to obtain:
$P_2=\frac{1.2\times 3.8}{0.075}$
This simplifies to:
$P_2=61atm$
