Answer
$V_2=31.8L$
Work Step by Step
Using Charles's law, we can find the final volume of the gas as follows:
$T_1=35+273.15=308.15K$
and $T_2=72+273.15=345.15K$
Now $\frac{V_1}{T_1}=\frac{V_2}{T_2}$
This can be rearranged as
$V_2=\frac{V_1T_2}{T_1}$
We plug in the known values to obtain:
$V_2=\frac{28.4}{308.15}\times 345.15$
This simplifies to:$
$V_2=31.8L$
