Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 10 - Questions and Problems - Page 471: 10.21

Answer

$V_2=45.9mL$

Work Step by Step

The final volume can be determined as follows: According to Boyle's law $P_1V_1=P_2V_2$ This can be rearranged as $V_2=\frac{P_1V_1}{P_2}$ We plug in the known values to obtain: $V_2=\frac{0.970\times 25.6}{0.541}$ This simplifies to: $V_2=45.9mL$
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