Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 315: 7.8

Answer

(a) $6.58\times10^{14}\,Hz$ (b) $1.22\times10^{8}\,nm$

Work Step by Step

(a) $c=\nu\lambda$ where $c$ is the speed of light, $\nu$ is the frequency and $\lambda$ is the wavelength. $\implies \nu=\frac{c}{\lambda}=\frac{3.00\times10^{8}\,m/s}{456\times10^{-9}\,m}=6.58\times10^{14}\,s^{-1}$ $=6.58\times10^{14}\,Hz$ (b) $\lambda=\frac{c}{\nu}=\frac{3.00\times10^{8}\,m/s}{2.45\times10^{9}\,s^{-1}}=0.122\,m=1.22\times10^{8}\times10^{-9}\,m$ $=1.22\times10^{8}\,nm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.