Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 315: 7.7

Answer

(a) 3500 nm (b) $5.30\times10^{14}\,Hz$

Work Step by Step

(a) $c=\nu\lambda$ where $c$ is the speed of light, $\nu$ is the frequency and $\lambda$ is the wavelength. $\implies\lambda=\frac{c}{\nu}=\frac{3.00\times10^{8}\,m/s}{8.6\times10^{13}\,s^{-1}}=3.5\times10^{-6}\,m=3500\,nm$ (b) $\lambda=566\,nm=566\times10^{-9}\,m$ $\nu=\frac{c}{\lambda}=\frac{3.00\times10^{8}\,m/s}{566\times10^{-9}\,m}=5.30\times10^{14}\,s^{-1}$ $=5.30\times10^{14}\,Hz$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.