## Chemistry 12th Edition

We know in the given scenario $Moles \space of \space NaOH:HCl=1:1$ We plug in the known values to obtain: $0.0174L\space HCl\times 0.312\frac{mol}{HCl}=0.0054mol\space NaOH$ $Molarity\space of\space NaOH=\frac{0.0054mol}{0.0025L}=0.217\frac{mol}{L}$