Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 4 - Reactions in Aqueous Solutions - Questions & Problems - Page 162: 4.75

Answer

Please see the work below.

Work Step by Step

We know that: $M_1V_1=M_2V_2$ Where $M_1$ is the concentration of the original solution and $V_1$ is the volume of the original solution. $M_2$ and $V_2$ are the concentration and final volume of the diluted solution, respectively. We plug in the known values into the above equation to obtain: $0.200\times 0.0600L=4.00\times V_2$ $V_1=0.00300L=3.0mL$
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