## Chemistry 12th Edition

Published by McGraw-Hill Education

# Chapter 4 - Reactions in Aqueous Solutions - Questions & Problems: 4.73

#### Answer

Please see the work below.

#### Work Step by Step

We know that $M_1V_1=M_2V_2$ Where $M_1$ is the concentration of the original solution and $V_1$ is the volume of the original solution. $M_2$ and $V_2$ are the concentration and final volume of the diluted solution, respectively. We plug in the known values into the above equation to obtain: $1L\times 0.646M=2.00M\times V_2$ $V_2=0.323L=323 \space mL$

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