Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Heat Transfer and Temperature Measurement - Page 39: 62


1440 J

Work Step by Step

We know, q = c×m×∆T where q is the heat, c is the specific heat, m is the mass and ∆T is the change in temperature. Given: c= 0.895 J/g m= 45.3 g and ∆T = 62.5°C- 27.0°C = 35.5°C We get by substitution: q= 0.895 J/g × 45.3 g × 35.5 = 1440 J
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