Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Heat Transfer and Temperature Measurement - Page 39: 53

Answer

Conversion: (a) 245°C in K = 518.15 K (b) 25.2 K in °C = -247.95 °C (c) 242.0°C in °F = 467.6 °F (d) 110.0°F in K =316.48 K

Work Step by Step

Conversion: (a) 245°C in K ___K = °C +273.15 K ___ K = 245 °C + 273.15° 518.15 K (b) 25.2 K in °C ___°C = K - 273.15° ___°C = 25.2 K - 273.15° -247.95 °C (c) 242.0°C in °F __ °F = 1.8°C +32 __ °F = (1.8*(242.0°C) )+32 467.6 °F (d) 110.0°F in K First convert °F to °C ___°C = $\frac{(F-32°)}{1.8}$ ___°C = $\frac{(110-32°)}{1.8}$ 43.33 °C Then, convert °C to K ___K = °C +273.15 K ___K = 43.33°C +273.15 K 316.48 K
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