Answer
$7.20\times10^{3}\, J$
Work Step by Step
Heat $q=mc\Delta T$ where $m$ is the mass, $c$ is the specific heat and $\Delta T$ is the change in temperature.
That is, $q=(78.2\, g) (4.184\, J/g\cdot^{\circ}C) (32.0^{\circ}C-10.0^{\circ}C)$
$=7.20\times10^{3}\, J$
