Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 6 - Section 6.2 - More on Trigonometric Equations - 6.2 Problem Set - Page 333: 57

Answer

$x=\{0.3630,2.1351\}$

Work Step by Step

$cos(x)+3sin(x)-2=0$ $[3sin(x)-2]^2=[-cos(x)]^2$ $9sin^2(x)-12sin(x)+4=cos^2(x)$ $9sin^2(x)-12sin(x)+4-cos^2(x)=0$ $9sin^2(x)-12sin(x)+4-[1-sin^2(x)]=0$ $9sin^2(x)-12sin(x)+4-1+sin^2(x)=0$ $10sin^2(x)-12sin(x)+3=0$ $sin(x)=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-12) \pm \sqrt{(-12)^2 - 4 (10)(3)}}{2(10)}=\frac{6+\sqrt{6}}{10},\frac{6-\sqrt{6}}{10}$ $sin(x)=\frac{6-\sqrt{6}}{10}=0.355$ $x=sin^{-1}(\frac{6-\sqrt{6}}{10})$ $x=0.3630$ $sin(x)=\frac{6-\sqrt{6}}{10}=0.845\;\;\;\;$ $x=sin^{-1}(\frac{6-\sqrt{6}}{10})$ $x=2.1351$ $x=\{0.3630,2.1351\}$
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