Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 399: 45a

$x = 32~t$ $y = 55.4~t-16~t^2+3$

We can find an equation for the horizontal position $x$: $x = (v~cos~\theta)~t$ $x = (64~cos~60^{\circ})~t$ $x = 32~t$ We can find an equation for the vertical position $y$: $y = (v~sin~\theta)~t-16~t^2+h$ $y = (64~sin~60^{\circ})~t-16~t^2+3$ $y = 55.4~t-16~t^2+3$