Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 399: 41a

Answer

$x = 82.7~t$ $y = 30.1~t-16~t^2+2$

Work Step by Step

$v = 88~ft/s$ $\theta = 20^{\circ}$ $h = 2$ We can find an expression for $x$ in terms of $t$: $x = (v~cos~\theta)(t)$ $x = (88~cos~20^{\circ})(t)$ $x = 82.7~t$ We can find an expression for $y$ in terms of $t$: $y = (v~sin~\theta)(t)-16~t^2+h$ $y = (88~sin~20^{\circ})(t)-16~t^2+2$ $y = 30.1~t-16~t^2+2$
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