Answer
$x = 82.7~t$
$y = 30.1~t-16~t^2+2$
Work Step by Step
$v = 88~ft/s$
$\theta = 20^{\circ}$
$h = 2$
We can find an expression for $x$ in terms of $t$:
$x = (v~cos~\theta)(t)$
$x = (88~cos~20^{\circ})(t)$
$x = 82.7~t$
We can find an expression for $y$ in terms of $t$:
$y = (v~sin~\theta)(t)-16~t^2+h$
$y = (88~sin~20^{\circ})(t)-16~t^2+2$
$y = 30.1~t-16~t^2+2$