Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 399: 39a

$x = 24~t$ $y = 24\sqrt{3}~t-16~t^2$

$v = 48~ft/s$ $\theta = 60^{\circ}$ $h = 0$ We can find an expression for $x$ in terms of $t$: $x = (v~cos~\theta)(t)$ $x = (48~cos~60^{\circ})(t)$ $x = 24~t$ We can find an expression for $y$ in terms of $t$: $y = (v~sin~\theta)(t)-16~t^2$ $y = (48~sin~60^{\circ})(t)-16~t^2$ $y = 24\sqrt{3}~t-16~t^2$