## Trigonometry (11th Edition) Clone

$$2\sin^2 x+3\sin x+1=(\sin x+1)(2\sin x+1)$$
$$A=2\sin^2 x+3\sin x+1$$ We would separate $3\sin x$ into $2\sin x$ and $\sin x$. $$A=(2\sin^2 x+2\sin x)+(\sin x+1)$$ $$A=2\sin x(\sin x+1)+(\sin x+1)$$ $$A=(\sin x+1)(2\sin x+1)$$