## Trigonometry (11th Edition) Clone

$$\frac{1}{\csc^2\theta}+\frac{1}{\sec^2\theta}=1$$
$$A=\frac{1}{\csc^2\theta}+\frac{1}{\sec^2\theta}$$ $$A=\Bigg(\frac{1}{\csc\theta}\Bigg)^2+\Bigg(\frac{1}{\sec\theta}\Bigg)^2$$ - Reciprocal Identities: $$\csc\theta=\frac{1}{\sin\theta}\hspace{2cm}\sec\theta=\frac{1}{\cos\theta}$$ Therefore, $$\frac{1}{\csc\theta}=\sin\theta\hspace{2cm}\frac{1}{\sec\theta}=\cos\theta$$ $$A=\sin^2\theta+\cos^2\theta$$ $$A=1$$ (Pythagorean Identity)