Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Trigonometric Identities - Section 5.2 Verifying Trigonometric Identities - 5.2 Exercises - Page 208: 19


$$(1+\sin t)^2+\cos^2t=2\sin t+2$$

Work Step by Step

$$A=(1+\sin t)^2+\cos^2t$$ $$A=(1+\sin^2t+2\sin t)+\cos^2 t$$ $$A=1+(\sin^2 t+\cos^2 t)+2\sin t$$ Following one Pythagorean Identity: $$\sin^2 t+\cos^2 t=1$$ we have $$A=1+1+2\sin t$$ $$A=2\sin t+2$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.