Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Trigonometric Identities - Section 5.2 Verifying Trigonometric Identities - 5.2 Exercises - Page 208: 24

Answer

$$\sec^2\theta-1=(\sec\theta-1)(\sec\theta+1)$$

Work Step by Step

$$A=\sec^2\theta-1$$ We factor the expression like normal, using $$a^2-b^2=(a-b)(a+b)$$ Therefore, $$A=(\sec\theta-1)(\sec\theta+1)$$
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