## Trigonometry (11th Edition) Clone

Published by Pearson

# Chapter 5 - Test - Page 250: 8d

#### Answer

Since $sin(A+B)$ is positive and $cos(A+B)$ is negative, the quadrant of $A+B$ must be quadrant II.

#### Work Step by Step

$sin(A+B) = \frac{33}{65}$ $cos(A+B) = -\frac{56}{65}$ Since $sin(A+B)$ is positive and $cos(A+B)$ is negative, the quadrant of $A+B$ must be quadrant II.

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