#### Answer

$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$

#### Work Step by Step

We can verify the identity:
$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$

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Published by
Pearson

ISBN 10:
978-0-13-421743-7

ISBN 13:
978-0-13421-743-7

$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$

We can verify the identity:
$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$

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