Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Test - Page 250: 12


$\frac{sin~2x}{cos~2x+1} = tan~x$

Work Step by Step

$\frac{sin~2x}{cos~2x+1} = \frac{2~sin~x~cos~x}{cos^2~x-sin^2~x+1}$ $\frac{sin~2x}{cos~2x+1} = \frac{2~sin~x~cos~x}{cos^2~x-sin^2~x+(sin^2~x+cos^2~x)}$ $\frac{sin~2x}{cos~2x+1} = \frac{2~sin~x~cos~x}{2cos^2~x}$ $\frac{sin~2x}{cos~2x+1} = \frac{sin~x}{cos~x}$ $\frac{sin~2x}{cos~2x+1} = tan~x$
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