Trigonometry (11th Edition) Clone

$t = 0.00417~s$
$V = 163~sin(\omega~t)$ The value of $V$ will be a maximum when $sin(\omega~t) = 1$, which first occurs when $\omega~t = \frac{\pi}{2}$ We can find the least positive value of $t$: $\omega~t = \frac{\pi}{2}$ $t = \frac{\pi}{2~\omega}$ $t = \frac{\pi}{(2)(120~\pi)}$ $t = \frac{1}{240}$ $t = 0.00417~s$