Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Test - Page 250: 15b


$t = 0.00417~s$

Work Step by Step

$V = 163~sin(\omega~t)$ The value of $V$ will be a maximum when $sin(\omega~t) = 1$, which first occurs when $\omega~t = \frac{\pi}{2}$ We can find the least positive value of $t$: $\omega~t = \frac{\pi}{2}$ $t = \frac{\pi}{2~\omega}$ $t = \frac{\pi}{(2)(120~\pi)}$ $t = \frac{1}{240}$ $t = 0.00417~s$
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