Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Test - Page 250: 8a


$sin(A+B) = \frac{33}{65}$

Work Step by Step

If the hypotenuse is 13, and the opposite side is 5, then the length of the adjacent side is $\sqrt{13^2-5^2} = 12$ If the hypotenuse is 5, and the adjacent side is 3, then the length of the opposite side is $\sqrt{5^2-3^2} = 4$ $sin(A+B) = sin~A~cos~B+sin~B~cos~A$ $sin(A+B) = (\frac{5}{13})(-\frac{3}{5})+(\frac{12}{13})(\frac{4}{5})$ $sin(A+B) = -\frac{15}{65}+\frac{48}{65}$ $sin(A+B) = \frac{33}{65}$
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