Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix D - Graphing Techniques - Exercises - Page 449: 66

Answer

Refer to the curve in Black in Graph I
1506960958

Work Step by Step

For $f(x) = \frac{1}{2}x^3 + 2$ when $x = 2, y = 6;$ $x = 0, y = 2;$ $x = -2, y = -2;$ As seen, $f(x) = \frac{1}{2}x^3 + 2$ is the vertical shrinking by half and the vertical translation up by 2 units of $f(x) = x^3.$ Domain = $(-\infty, \infty)$ Range = $(-\infty, \infty)$
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