Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix D - Graphing Techniques - Exercises - Page 449: 62

Answer

Refer to the curve in Black in Graph I
1506959663

Work Step by Step

For $f(x) = \sqrt{x} - 2$ when $x = 9, y = 1;$ $x = 4, y = 0;$ $x = 1, y = -1;$ $x = 0, y = -2$ As seen, $f(x) = \sqrt{x} - 2$ is the vertical translation down by 2 units of $f(x) = \sqrt{x}$. Domain = $[0, \infty)$ Range = $[-2, \infty)$
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