Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix D - Graphing Techniques - Exercises - Page 449: 55

Answer

Refer to the curve in Black in Graph I
1506957174

Work Step by Step

For $y = 2x^2 - 1,$ when $x = 2, y = 7;$ $x = 1, y = 1;$ $x = 0, y = -1;$ $x = -1, y = 1;$ $x = -2, y = 7$ As seen, $y = 2x^2 - 1$ is the vertical stretching of $y = x^2$ twice and then with a vertical translation of 1 unit down. Domain = $(−\infty, \infty)$ Range = $[-1, \infty)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.