## Trigonometry (11th Edition) Clone

For $f(x) = \sqrt{x + 2}$ when $x = 7, y = 3;$ $x = 2, y = 2;$ $x = -1, y = 1;$ $x = -2, y = 0$ As seen, $f(x) = \sqrt{x + 2}$ is the horizontal translation to the left by 2 units of $f(x) = \sqrt{x}$. Domain = $[−2, \infty)$ Range = $[0, \infty)$