Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix D - Graphing Techniques - Exercises - Page 449: 59

Answer

Refer to the curve in Black in Graph I
1506958735

Work Step by Step

For $f(x) = \sqrt{x + 2}$ when $x = 7, y = 3;$ $x = 2, y = 2;$ $x = -1, y = 1;$ $x = -2, y = 0$ As seen, $f(x) = \sqrt{x + 2}$ is the horizontal translation to the left by 2 units of $f(x) = \sqrt{x}$. Domain = $[−2, \infty)$ Range = $[0, \infty)$
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