Answer
Refer to the curve in Black in Graph I

Work Step by Step
For $f(x) = 2\sqrt{x} + 1$
when
$x = 9, y = 7;$
$x = 4, y = 5;$
$x = 1, y = 3;$
$x = 0, y = 1$
As seen, $f(x) = 2\sqrt{x} + 1$ is the vertical stretching twice and the vertical translation up by 1 unit of $f(x) = \sqrt{x}$.
Domain = $[0, \infty)$
Range = $[1, \infty)$