Answer
Refer to the curve in Black in Graph I
![](https://gradesaver.s3.amazonaws.com/uploads/solution/b77279c2-47f9-4923-97f6-0efaec887293/result_image/1506959974.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T022534Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=9aa041627c9b1f7290124e02ed3b85b5db460a84d74db173e2fae1cdd0280af7)
Work Step by Step
For $f(x) = 2\sqrt{x} + 1$
when
$x = 9, y = 7;$
$x = 4, y = 5;$
$x = 1, y = 3;$
$x = 0, y = 1$
As seen, $f(x) = 2\sqrt{x} + 1$ is the vertical stretching twice and the vertical translation up by 1 unit of $f(x) = \sqrt{x}$.
Domain = $[0, \infty)$
Range = $[1, \infty)$