Chapter 7 - Section 7.2 - Assess Your Understanding - Applying the Concepts - Page 378: 39c

$P(x > 1200)$ = 0.7019

Want to find $P( x > 1200)$ i) Convert 1200 to a z-score: z = $\frac{x - \mu}{\sigma}$ z = $\frac{1200 - 1262}{118}$ z= -0.53 ii) $P(x > 1200) = P(z > -0.53)$ $P(z > -0.53)$ $= 1- P(z < -0.53)$ $= 1 - 0.2981 $ $= 0.7019$ Therefore, $P(x > 1200)$ = 0.7019