Answer
$P(x < 100)$ = 0.1492
Work Step by Step
$\mu$ = 125, $\sigma$ = 24
Want to find $P(x < 100)$:
i) Convert 100 to a z-score
z = $\frac{100 - 125}{24}$
z $\approx$ -1.04
ii) $P(x < 100) = P(z < -1.04)$
From table V we have $P(z < -1.04)$ = 0.1492
Therefore, $P(x < 100)$ = 0.1492
