Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 7 - Section 7.2 - Assess Your Understanding - Applying the Concepts - Page 378: 38c

Answer

The probability that a randomly selected sixth-grade student reads between 110 and 130 words per minute is 0.3189

Work Step by Step

$\mu$ = 125, $\sigma$ = 24 Want to find $P(110 < x < 130)$: i) Convert 110 to a z-score: z = $\frac{x - \mu}{\sigma}$ z = $\frac{110 - 125}{24}$ z $\approx$ -0.63 ii) Convert 130 to a z score: z = $\frac{130 - 125}{24}$ z $\approx$ 0.21 iii) $P(110 < x < 130) = P(-0.63 < z < 0.21)$ $P(-0.63 < z < 0.21)$ $= P(z \leq 0.21) - P(z \leq -0.63) = 0.5832 - 0.2643 = 0.3189$ Therefore $P(110 < x < 130) = 0.3189$
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