Answer
$P(2\leq~x\leq4)=0.400$
Work Step by Step
$P(2\leq~x\leq4)=P(2)+P(3)+P(4)=\frac{5^{2}}{2!}e^{-5}+\frac{5^{3}}{3!}e^{-5}+\frac{5^{4}}{4!}e^{-5}=\frac{25}{2}e^{-5}+\frac{125}{6}e^{-5}+\frac{625}{24}e^{-5}=0.400$
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