Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 6 - Section 6.3 - Assess Your Understanding - Vocabulary and Skill Building - Page 351: 10b

Answer

$P(x\lt2)=0.736$

Work Step by Step

$P(x\lt2)=P(0)+P(1)=\frac{(0.02\times50)^{0}}{0!}e^{-0.02\times50}+\frac{(0.02\times50)^{1}}{1!}e^{-0.02\times50}=\frac{1}{1}e^{-1}+\frac{1}{1}e^{-1}=0.736$
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