Answer
$P(1\leq~x\leq3)=0.613$
Work Step by Step
$P(1\leq~x\leq3)=P(1)+P(2)+P(3)=\frac{(0.02\times50)^1}{1!}e^{-0.02\times50}+\frac{(0.02\times50)^2}{2!}e^{-0.02\times50}+\frac{(0.02\times50)^3}{3!}e^{-0.02\times50}=\frac{1}{1}e^{-1}+\frac{1}{2}e^{-1}+\frac{1}{6}e^{-1}=0.613$
