Answer
$P(2)=0.184$
Work Step by Step
$P(x)=\frac{(λt)^{x}}{x!}e^{-λt}$
For λ = 0.02, t = 50 and x = 2
$P(2)=\frac{(0.02\times50)^{2}}{2!}e^{-0.02\times50}=\frac{1^2}{2}e^{-1}=0.184$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 6 - Section 6.3 - Assess Your Understanding - Vocabulary and Skill Building - Page 351: 10a
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