Chapter 6 - Section 6.3 - Assess Your Understanding - Applying the Concepts - Page 352: 21c

$P(0)=0.543$ $P(1)=0.331$ $P(2)=0.101$ $P(3)=0.0206$ $P(4)=0.00313$

$P(x)=\frac{μ^x}{x!}e^{-μ}$ $μ = 0.61$ $P(0)=\frac{0.61^0}{0!}e^{-0.61}=0.543$ $P(1)=\frac{0.61^1}{1!}e^{-0.61}=0.331$ $P(2)=\frac{0.61^2}{2!}e^{-0.61}=0.101$ $P(3)=\frac{0.61^3}{3!}e^{-0.61}=0.0206$ $P(4)=\frac{0.61^4}{4!}e^{-0.61}=0.00313$