Answer
$μ_X=0.61$
Work Step by Step
$μ_X=Σ[x.P(x)]=0\times P(0)+1\times P(1)+2\times P(3)+4\times P(4)=0\times0.545+1\times0.325+2\times0.11+3\times0.015+4\times0.005=0.61$
OR
$μ_X=\frac{Σ[x_if_i.]}{N}=\frac{0\times109+1\times65+2\times22+3\times3+4\times1}{200}=0.61$