Answer
$P(at~least~two~people~share~the~same~birthday)=0.5073$
Work Step by Step
If we follow the same procedure given in Problem 33:
$P(23~people~have~23~different~birthdays)=\frac{365}{365}\times\frac{364}{365}\times\frac{363}{365}\times\frac{362}{365}\times\frac{361}{365}\times\frac{360}{365}\times\frac{359}{365}\times\frac{358}{365}\times\frac{357}{365}\times\frac{356}{365}\times\frac{355}{365}\times\frac{354}{365}\times\frac{353}{365}\times\frac{352}{365}\times\frac{351}{365}\times\frac{350}{365}\times\frac{349}{365}\times\frac{348}{365}\times\frac{347}{365}\times\frac{346}{365}\times\frac{345}{365}\times\frac{344}{365}\times\frac{343}{365}\approx0.4927$
$P(at~least~two~people~share~the~same~birthday)=1-P(23~people~have~23~different~birthdays)=1-0.4927=0.5073$
