Answer
$P(female~and~smoker)=0.090335$
It is not an unusual event.
Work Step by Step
$20.3$% $=0.203$, $44.5$% $=0.445$
$P(smoker)=0.203$ and $P(female~|~smoker)=0.445$
Using the General Multiplication Rule (page 289):
$P(female~and~smoker)=P(smoker)\times P(female~|~smoker)=0.203\times0.445=0.090335$
$P(female~and~smoker)\gt0.05$. So, it is not an unusual event.