Answer
$\mu=60$
$\sigma^2=24$
$\sigma=4.90$
Work Step by Step
$q=1-p=1-.6=.4$
$\mu=np=100(.6)=60$
$\sigma^2=npq=100(.6)(.4)=24$
$\sigma=\sqrt {24}=4.90$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 4 - Discrete Random Variables - Exercises 4.50 - 4.76 - Learning the Mechanics - Page 205: 4.57c
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