Answer
$p(0)=.027$
Work Step by Step
$q=1-p=1-.7=.3$
$p(x)=\begin{pmatrix} n \\ x \end{pmatrix}p^xq^{n-x}$
$p(0)=\begin{pmatrix} 3 \\ 0 \end{pmatrix}.3^0.3^{3-0}=\frac{3!}{0!(3-0)!}1(.3)^3=.027$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 4 - Discrete Random Variables - Exercises 4.50 - 4.76 - Learning the Mechanics - Page 205: 4.55c
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