Answer
$p(1)=0.027$
Work Step by Step
$q=1-p=1-.9=.1$
$p(x)=\begin{pmatrix} n \\ x \end{pmatrix}p^xq^{n-x}$
$p(1)=\begin{pmatrix} 3 \\ 1 \end{pmatrix}(.9)^1(.1)^{3-1}=\frac{3!}{1!(3-1)!}(.9)(.1)^2=\frac{3(2!)}{2!}(.9)(.01)=3(.009)=0.027$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 4 - Discrete Random Variables - Exercises 4.50 - 4.76 - Learning the Mechanics - Page 205: 4.55f
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