Answer
$p(1)=.4096$
Work Step by Step
$q=1-p=1-.2=.8$
$p(x)=\begin{pmatrix} n\\x\end{pmatrix}p^xq^{n-x}$
$p(1)=\begin{pmatrix} 5\\1\end{pmatrix}.2^1.8^{5-1}=\frac{5!}{1!(5-1)!}(.2)(.8)^4=\frac{5(4!)}{4!}(.2)(.8)^4=.4096$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 4 - Discrete Random Variables - Exercises 4.50 - 4.76 - Learning the Mechanics - Page 205: 4.55a
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